Find the product by suitable rearrangement 8 x453 x125​

Find the product by suitable rearrangement 8 x453 x125​

To find the product of 8, 453, and 125, we can rearrange the numbers in a way that makes multiplication easier. Let's rewrite the numbers as follows:

8 = 2^3

453 = 3 x 151

125 = 5^3

Now we can rearrange the numbers:

8 x 453 x 125 = (2^3) x (3 x 151) x (5^3)

Using the properties of exponents, we can simplify the expression:

(2^3) x (3 x 151) x (5^3) = 2^(3+3) x 3 x 151 x 5^3

= 2^6 x 3 x 151 x 5^3

Now, we can calculate the product:

2^6 = 64

3 x 151 = 453

5^3 = 125

Therefore,

8 x 453 x 125 = 64 x 453 x 125 = 3,609,000.

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Answer:

The product of 8 * 453 * 125 is 453000.

Step-by-step explanation:

We can rearrange the factors to make the multiplication easier.

For example, we can group the 8 and the 125 together to get 8 * 125 = 1000. We can then multiply this by 453 to get 453000.

Another way to rearrange the factors is to group the 453 and the 125 together to get 453 * 125 = 56625. We can then multiply this by 8 to get 453000.

No matter how we rearrange the factors, the product will always be 453000.

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